Laptop Model: Dell Latitude
E7450
Board Number : LA-A961P
Fault: There is a short circuit when powering on a large current of 1A,
and there is a power outage inside.
Repair Process:
After disassembling the
inductors, a short circuit was found. The common point short circuit resistance
was 00. Run the line from the adapter to find the initial common point
isolation tube. It was found that the first self-conducting isolation tube had
broken down and replaced it.
It was found that the 5V upper tube broke down and was replaced,
and the resistance of the common point returned to more than 200. There must be
other places.
I also tested the battery and found that the resistance of the battery charge sense and the common point was 0. After the PQ705 composite tube broke down and was replaced, the common point was broken down. The point resistance value returned to more than 400 normal.
It is abnormal to find that the resistance of the battery inductor is only a few tens of ohms. When the front end of the disconnected inductor is disconnected, the resistance is a few hundred, but the back end is only a few tens.
There is something wrong with the back
end. I ran the circuit and found that there was nothing abnormal around
it. I burned it directly and connected it to 3V and found that a filter
capacitor on the back was hot.
The common
point and various places are not shorted, and there is nothing when it is
powered on and in standby mode. The common point is only 18V when measured, and
the adapter is a false common point of 19.5V.
When measuring
the isolation, it is found that the PQ700 G pole voltage is the same as the
common point voltage, 19.5V. How can it be turned on? Continuing to run
the line, I found that the PQ700 G pole is controlled by PU700.
The PU700 chip
drawing was not found. I found a drawing in Google. DELL uses this chip. I
checked that the chip condition is normal, that is, the internal output is
19.5V.
After
replacing the chip, PQ700 is turned on, the common point voltage is normal at
19.5, and there is standby current. When the trigger is pressed, there is
no 3V5VPWM output.
The value of
the inductor is more than 400, which is normal. When testing the standby chip
conditions, the power supply is normal. The EC normally sends out a start
signal, and the wired core has a benchmark.
Replace the
standby chip and press the trigger 3V5V to come out. Turn off the power
immediately after powering on, install the CPU cooler and memory, run the code
directly and turn on the Laptop.
This is the
end of the repair!
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